In a certain liberal arts college with about 10,000 students, 40% are males. If two students from this college are selected at random, what is the probability that they are both males? 0 0.16 0.80 0.64 0.25
Question
In a certain liberal arts college with about 10,000 students, 40% are males. If two students from this college are selected at random, what is the probability that they are both males? 0 0.16 0.80 0.64 0.25
Solution
The problem can be solved using the concept of probability. Here are the steps:
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First, find out the total number of male students in the college. Since 40% of 10,000 students are males, there are 0.40 * 10,000 = 4,000 male students.
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The probability of selecting a male student at random is the number of male students divided by the total number of students. So, the probability of the first student being male is 4,000 / 10,000 = 0.40.
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If one male student is already selected, there are now 3,999 male students left and the total number of students is 9,999. So, the probability of the second student being male is 3,999 / 9,999 = 0.40 (approximately).
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The probability of both students being male is the product of the probability of the first student being male and the probability of the second student being male. So, the probability is 0.40 * 0
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