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Select the correct answerA schoolyard contains only bicycles and 4 wheeled wagons. On Tuesday, the total number of wheels in the schoolyard was 166. What could the possible number of bicycles?radio_button_unchecked14radio_button_unchecked10radio_button_unchecked12radio_button_unchecked11

Question

Select the correct answerA schoolyard contains only bicycles and 4 wheeled wagons. On Tuesday, the total number of wheels in the schoolyard was 166. What could the possible number of bicycles?radio_button_unchecked14radio_button_unchecked10radio_button_unchecked12radio_button_unchecked11

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Solution

To solve this problem, we need to set up an equation based on the information given.

Let's denote: B = number of bicycles W = number of wagons

Each bicycle has 2 wheels and each wagon has 4 wheels. So, the total number of wheels is given by the equation:

2B + 4W = 166

We also know that the number of bicycles and wagons must be a whole number.

Let's check each of the given options:

  1. If B = 14, then the equation becomes 2*14 + 4W = 166, which simplifies to 28 + 4W = 166. Solving for W gives W = 34.5, which is not a whole number. So, B cannot be 14.

  2. If B = 10, then the equation becomes 2*10 + 4W = 166, which simplifies to 20 + 4W = 166. Solving for W gives W = 36.5, which is not a whole number. So, B cannot be 10.

  3. If B = 12, then the equation becomes 2*12 + 4W = 166, which simplifies to 24 + 4W = 166. Solving for W gives W = 35.5, which is not a whole number. So, B cannot be 12.

  4. If B = 11, then the equation becomes 2*11 + 4W = 166, which simplifies to 22 + 4W = 166. Solving for W gives W = 36, which is a whole number. So, B can be 11.

Therefore, the correct answer is 11.

This problem has been solved

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