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Select the correct answerWhat will be the output of the following Java code? class Name {     public static void main(String args[]) {          try {             int ct1 = 0;             int ct2 = 5;             int ct3 = ct2 / ct1;             System.out.print("Hello");         }         catch(Exception e) {             System.out.print("CodeTantra");         }      } }OptionsHelloHelloCodeTantraCompilation ErrorCodeTantra

Question

Select the correct answerWhat will be the output of the following Java code? class Name {     public static void main(String args[]) {          try {             int ct1 = 0;             int ct2 = 5;             int ct3 = ct2 / ct1;             System.out.print("Hello");         }         catch(Exception e) {             System.out.print("CodeTantra");         }      } }OptionsHelloHelloCodeTantraCompilation ErrorCodeTantra

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Solution

The correct answer is "CodeTantra".

Here's the step-by-step explanation:

  1. The main method is the entry point of the Java program.

  2. The program starts executing and enters the try block.

  3. It initializes two integer variables, ct1 with 0 and ct2 with 5.

  4. Then it tries to perform the operation ct2/ct1. Since ct1 is 0, this operation results in a division by zero, which is undefined in mathematics.

  5. In Java, division by zero leads to an ArithmeticException.

  6. Since the exception occurs inside the try block, the control is immediately transferred to the catch block, skipping the rest of the code in the try block.

  7. Therefore, "Hello" is not printed to the console.

  8. In the catch block, "CodeTantra" is printed to the console.

  9. Hence, the output of the program is "CodeTantra".

This problem has been solved

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