To solve this problem, we need to use the principles of combinatorics. Here are the steps:

1. First, we need to ensure that each box has at least one ball. We can do this in 5P3 = 5*4*3 = 60 ways.

2. Now, we have 2 balls left and 3 boxes. We can distribute these 2 balls in 3^2 = 9 ways.

3. Therefore, the total number of ways we can distribute the balls so that no box remains empty is 60*9 = 540 ways.

Question

To solve this problem, we need to use the principles of combinatorics. Here are the steps:

1. First, we need to ensure that each box has at least one ball. We can do this in 5P3 = 5*4*3 = 60 ways.

2. Now, we have 2 balls left and 3 boxes. We can distribute these 2 balls in 3^2 = 9 ways.

3. Therefore, the total number of ways we can distribute the balls so that no box remains empty is 60*9 = 540 ways.

Knowee AI · Accepted Answer

To solve this problem, we need to use the principles of combinatorics. Here are the steps:

1. First, we need to ensure that each box has at least one ball. We can do this in 5P3 = 5*4*3 = 60 ways.

2. Now, we have 2 balls left and 3 boxes. We can distribute these 2 balls in 3^2 = 9 ways.

3. Therefore, the total number of ways we can distribute the balls so that no box remains empty is 60*9 = 540 ways.

Five balls of different colours are to be placed in three boxes of different sizes. Each box can hold all five balls. In how many ways can we place the balls so that no box remains empty?50100150200