Sure, here is a Python program that prints a spiral matrix for a given matrix:

```python
def spiralPrint(m, n, a) :
k = 0; l = 0

while (k

Question

Sure, here is a Python program that prints a spiral matrix for a given matrix:

```python
def spiralPrint(m, n, a) :
    k = 0; l = 0
 
    while (k < m and l < n) :
        for i in range(l, n) :
            print(a[k][i], end = " ")
             
        k += 1
 
        for i in range(k, m) :
            print(a[i][n - 1], end = " ")
             
        n -= 1
 
        if ( k < m) :
             
            for i in range(n - 1, (l - 1), -1) :
                print(a[m - 1][i], end = " ")
             
            m -= 1
         
        if (l < n) :
            for i in range(m - 1, k - 1, -1) :
                print(a[i][l], end = " ")
             
            l += 1
 
# Test the above function
a = [ [1, 2, 3, 4, 5, 6],
      [7, 8, 9, 10, 11, 12],
      [13, 14, 15, 16, 17, 18] ]
       
spiralPrint(3, 6, a)
```

This program works by printing the first row from the remaining rows, then the last column from the remaining columns, then the last row from the remaining rows (from right to left), and then the first column from the remaining columns (from bottom to top). We keep doing this while there are rows and columns left to be printed.

Knowee AI · Accepted Answer

Sure, here is a Python program that prints a spiral matrix for a given matrix:

```python
def spiralPrint(m, n, a) :
    k = 0; l = 0
 
    while (k < m and l < n) :
        for i in range(l, n) :
            print(a[k][i], end = " ")
             
        k += 1
 
        for i in range(k, m) :
            print(a[i][n - 1], end = " ")
             
        n -= 1
 
        if ( k < m) :
             
            for i in range(n - 1, (l - 1), -1) :
                print(a[m - 1][i], end = " ")
             
            m -= 1
         
        if (l < n) :
            for i in range(m - 1, k - 1, -1) :
                print(a[i][l], end = " ")
             
            l += 1
 
# Test the above function
a = [ [1, 2, 3, 4, 5, 6],
      [7, 8, 9, 10, 11, 12],
      [13, 14, 15, 16, 17, 18] ]
       
spiralPrint(3, 6, a)
```

This program works by printing the first row from the remaining rows, then the last column from the remaining columns, then the last row from the remaining rows (from right to left), and then the first column from the remaining columns (from bottom to top). We keep doing this while there are rows and columns left to be printed.

Write a Python program to print spiral matrix for a given matrix.

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