If f(x) = x2 - bx + 15 and (2, 3) is an ordered pair that satisfies f(x), what is the value of 6b?(A) -12(B) 18(C) 36(D) 48
Question
If f(x) = x2 - bx + 15 and (2, 3) is an ordered pair that satisfies f(x), what is the value of 6b?(A) -12(B) 18(C) 36(D) 48
Solution
Given that (2,3) is an ordered pair that satisfies f(x), we can substitute x = 2 and f(x) = 3 into the equation.
So, 3 = (2)^2 - b*2 + 15
Solving this equation for b, we get:
3 = 4 - 2b + 15
Rearranging terms, we get:
2b = 4 + 15 - 3
2b = 16
So, b = 16 / 2 = 8
The question asks for the value of 6b, so we multiply b by 6:
6b = 6 * 8 = 48
So, the value of 6b is 48. Therefore, the answer is (D) 48.
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