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What would be output at the end of the following code segment? int num = 0; for(int row = 0; row < 8; row++ ) { for(int col = 0; col < 0; col++) { num++; } } System.out.println(num);error180

Question

What would be output at the end of the following code segment? int num = 0; for(int row = 0; row < 8; row++ ) { for(int col = 0; col < 0; col++) { num++; } } System.out.println(num);error180

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Solution

The output of the code will be 0.

Here's the step by step explanation:

  1. An integer variable num is initialized with the value 0.
  2. A for loop is set up to run 8 times, with row incrementing from 0 to 7.
  3. Inside this for loop, another for loop is set up to run from 0 to -1 (which is less than 0). However, since the condition for this loop to run is col < 0, and col is initialized to 0, this inner loop will never run.
  4. Therefore, num++ inside the inner loop will never be executed.
  5. After both loops have finished executing, the value of num (which is still 0) is printed to the console.

So, the output of the code will be 0.

This problem has been solved

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