The problem is asking to sort an array of 0's and 1's in ascending order using the two-pointer technique. Here is a step-by-step solution in Python:

1. First, initialize two pointers, `left` and `right`. `left` is initialized as 0, which is the starting index of the array, and `right` is initialized as `n-1`, which is the last index of the array.

2. Run a while loop until `left` is less than or equal to `right`.

3. In the while loop, check if the left element is 0. If it is, then just increase the `left` pointer, because 0 is at its correct position (at the start of the array).

4. If the left element is 1, then check if the right element is 0. If it is, then swap the left and right elements and increase the `left` pointer and decrease the `right` pointer.

5. If the right element is not 0, then just decrease the `right` pointer.

6. Repeat steps 3 to 5 until `left` is not less than or equal to `right`.

7. Print the sorted array.

Here is the Python code for the above steps:

```python
T = int(input())
for _ in range(T):
N = int(input())
arr = list(map(int, input().split()))
left, right = 0, N - 1
while left

Question

The problem is asking to sort an array of 0's and 1's in ascending order using the two-pointer technique. Here is a step-by-step solution in Python:

1. First, initialize two pointers, `left` and `right`. `left` is initialized as 0, which is the starting index of the array, and `right` is initialized as `n-1`, which is the last index of the array.

2. Run a while loop until `left` is less than or equal to `right`.

3. In the while loop, check if the left element is 0. If it is, then just increase the `left` pointer, because 0 is at its correct position (at the start of the array).

4. If the left element is 1, then check if the right element is 0. If it is, then swap the left and right elements and increase the `left` pointer and decrease the `right` pointer.

5. If the right element is not 0, then just decrease the `right` pointer.

6. Repeat steps 3 to 5 until `left` is not less than or equal to `right`.

7. Print the sorted array.

Here is the Python code for the above steps:

```python
T = int(input())
for _ in range(T):
    N = int(input())
    arr = list(map(int, input().split()))
    left, right = 0, N - 1
    while left <= right:
        if arr[left] == 0:
            left += 1
        else:
            if arr[right] == 0:
                arr[left], arr[right] = arr[right], arr[left]
                left += 1
            right -= 1
    print(*arr)
```

This code reads the number of test cases, then for each test case, it reads the size of the array and the array itself. It sorts the array using the two-pointer technique and then prints the sorted array.

Knowee AI · Accepted Answer