Given the following "IAS" instructions:Opcode Assembly Code: Description00000001 LOAD M(X) Transfer the contents of memorylocation X to AC.00100001 sroR M(x) Transfer the contents of AC tomemory location X.00000101 ADD M(X) Add thLe contents of memorylocation X to AC.Show the assembly language program segment for the followinginstructions and explain what the program segment does.00000001 000000000100 00000101 00000000010000000101 000000001000 00100001 000000001000

The given assembly language program segment consists of the following instructions:

1. 00000001: LOAD M(X) This instruction transfers the contents of memory location X to the AC (accumulator).

2. 00000001 000000000100: LOAD M(4) This instruction transfers the contents of memory location 4 to the AC.

3. 00000101: ADD M(X) This instruction adds the contents of memory location X to the AC.

4. 00000001 000000000100: LOAD M(4) This instruction transfers the contents of memory location 4 to the AC.

5. 00000101: ADD M(X) This instruction adds the contents of memory location X to the AC.

6. 00000010 000000001000: STOR M(8) This instruction transfers the contents of the AC to memory location 8.

The program segment performs the following steps:

1. It loads the contents of memory location 4 into the AC.
2. It adds the contents of memory location X (which is also 4) to the AC.
3. It loads the contents of memory location 4 into the AC again.
4. It adds the contents of memory location X (which is still 4) to the AC.
5. Finally, it stores the contents of the AC into memory location 8.

In summary, this program segment loads the value from memory location 4, adds it to itself twice, and then stores the result in memory location 8.