The power rating of a resistor can be calculated using Ohm's Law, which states that the power (P) is equal to the current (I) squared times the resistance (R). This can be written as:

P = I^2 * R

Given that the current (I) is 25 mA (or 0.025 A) and the resistance (R) is 120 Ω, we can substitute these values into the equation:

P = (0.025 A)^2 * 120 Ω = 0.075 W or 75 mW

Therefore, the rating of the resistor should be at least 75 mW.

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The power rating of a resistor can be calculated using Ohm's Law, which states that the power (P) is equal to the current (I) squared times the resistance (R). This can be written as:

P = I^2 * R

Given that the current (I) is 25 mA (or 0.025 A) and the resistance (R) is 120 Ω, we can substitute these values into the equation:

P = (0.025 A)^2 * 120 Ω = 0.075 W or 75 mW

Therefore, the rating of the resistor should be at least 75 mW.

Knowee AI · Accepted Answer

The power rating of a resistor can be calculated using Ohm's Law, which states that the power (P) is equal to the current (I) squared times the resistance (R). This can be written as:

P = I^2 * R

Given that the current (I) is 25 mA (or 0.025 A) and the resistance (R) is 120 Ω, we can substitute these values into the equation:

P = (0.025 A)^2 * 120 Ω = 0.075 W or 75 mW

Therefore, the rating of the resistor should be at least 75 mW.

A 120 Ω resistor must carry a maximum current of 25 mA. Its rating should be at least

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