Raj buys two clocks for Rs. 840. He sells one of the clocks at 8% profit and the other at a loss of 6%. Thus, as a whole he neither gains nor loses. Find the cost price of each clock

Let's denote the cost price of the first clock as x and the cost price of the second clock as y.

According to the problem, Raj buys two clocks for Rs. 840. So, we have the equation:

x + y = 840

Raj sells the first clock at 8% profit and the second clock at a loss of 6%. But overall, he neither gains nor loses. This means the amount he gained on the first clock is equal to the amount he lost on the second clock. So, we have the second equation:

8/100 * x = 6/100 * y

Now we have a system of two equations, and we can solve it step by step.

First, let's simplify the second equation. We can multiply both sides by 100 to get rid of the fractions:

8x = 6y

Then, we can express y through x using this equation:

y = 8x / 6 = 4x / 3

Now we can substitute y in the first equation:

x + 4x / 3 = 840

Multiply all terms by 3 to clear the fraction:

3x + 4x = 2520

Combine like terms:

7x = 2520

Finally, solve for x:

x = 2520 / 7 = 360

Substitute x = 360 in the equation y = 4x / 3 to find y:

y = 4 * 360 / 3 = 480

So, the cost price of the first clock is Rs. 360 and the cost price of the second clock is Rs. 480.