Suppose that a certain semiconductor memory chip has a capacity of 8K × 8. How many bytes could be stored in this device?a.8000b.64000c.8192d. 65,536
Question
Suppose that a certain semiconductor memory chip has a capacity of 8K × 8. How many bytes could be stored in this device?a.8000b.64000c.8192d. 65,536
Solution
The capacity of a semiconductor memory chip is often given in the format of 'K x N', where 'K' represents the number of memory locations and 'N' represents the number of bits per memory location.
In this case, the chip has a capacity of 8K x 8.
1K is equivalent to 1024 (as it's based on binary system), so 8K is 8 * 1024 = 8192 memory locations.
Each memory location stores 8 bits of data, and 1 byte is equal to 8 bits.
So, the total storage capacity of the chip in bytes is 8192 memory locations * 1 byte/location = 8192 bytes.
Therefore, the correct answer is c. 8192.
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