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18b+18b–11≤–3(–11b–2)–20

Question

18b+18b–11≤–3(–11b–2)–20

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Solution

Sure, let's solve this inequality step by step:

  1. Simplify the left side of the inequality: 18b + 18b - 11 = 36b - 11
  2. Distribute the -3 on the right side of the inequality: -3(-11b - 2) - 20 = 33b + 6 - 20 = 33b - 14
  3. So the inequality becomes: 36b - 11 ≤ 33b - 14
  4. Subtract 33b from both sides: 36b - 33b ≤ -14 + 11
  5. This simplifies to: 3b ≤ -3
  6. Finally, divide both sides by 3 to solve for b: b ≤ -1

So the solution to the inequality is b ≤ -1.

This problem has been solved

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