The logarithmic function f(x) = ln(x - 6) has the vertical asymptote x = 6.

Here's why:

A logarithmic function of the form f(x) = ln(x - h) has a vertical asymptote at x = h. This is because the natural logarithm function ln(x) is undefined for x ≤ 0. Therefore, for the function f(x) = ln(x - 6), the value inside the logarithm (x - 6) must be greater than 0.

Setting x - 6 0 and solving for x gives x 6.

Therefore, the function is undefined at x = 6, and x = 6 is a vertical asymptote of the function.

Question

The logarithmic function f(x) = ln(x - 6) has the vertical asymptote x = 6.

Here's why:

A logarithmic function of the form f(x) = ln(x - h) has a vertical asymptote at x = h. This is because the natural logarithm function ln(x) is undefined for x ≤ 0. Therefore, for the function f(x) = ln(x - 6), the value inside the logarithm (x - 6) must be greater than 0.

Setting x - 6 > 0 and solving for x gives x > 6.

Therefore, the function is undefined at x = 6, and x = 6 is a vertical asymptote of the function.

Knowee AI · Accepted Answer

The logarithmic function f(x) = ln(x - 6) has the vertical asymptote x = 6.

Here's why:

A logarithmic function of the form f(x) = ln(x - h) has a vertical asymptote at x = h. This is because the natural logarithm function ln(x) is undefined for x ≤ 0. Therefore, for the function f(x) = ln(x - 6), the value inside the logarithm (x - 6) must be greater than 0.

Setting x - 6 > 0 and solving for x gives x > 6.

Therefore, the function is undefined at x = 6, and x = 6 is a vertical asymptote of the function.

The logarithmic function f(x) = ln(x − 6) has the asymptote x =

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