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Understanding Logical operators#include <stdio.h>void main() { int a = 10, b = 5, c = 3; b = !a; c = !!a; printf("%d %d", b, c);}Fill the correct output of the given code

Question

Understanding Logical operators#include <stdio.h>void main() { int a = 10, b = 5, c = 3; b = !a; c = !!a; printf("%d %d", b, c);}Fill the correct output of the given code

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Solution

The given code is written in C language and it is using logical operators. The logical NOT operator (!) is used here. This operator is used to reverse the logical state of its operand. If a condition is true, then the Logical NOT operator will make it false.

Here is the step by step explanation:

  1. The variables a, b, and c are declared and initialized. The variable 'a' is assigned a value of 10.

  2. The expression '!a' is evaluated. Since 'a' is non-zero, it is considered as true. The logical NOT operator (!) will reverse this to false. In C, false is represented by 0. So, 'b' is assigned a value of 0.

  3. The expression '!!a' is evaluated. The first NOT operator will make 'a' false (as explained in the previous step) and the second NOT operator will reverse this again to true. In C, true is represented by 1. So, 'c' is assigned a value of 1.

  4. The printf function is used to print the values of 'b' and 'c'.

So, the output of the given code will be "0 1".

This problem has been solved

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