An object is released from rest at t = 0. How far does it fall during the first second after release?Neglect air friction and express your answer in meters.
Question
An object is released from rest at t = 0. How far does it fall during the first second after release?Neglect air friction and express your answer in meters.
Solution 1
The distance an object
Solution 2
The distance an object falls when dropped from rest can be calculated using the equation of motion:
d = 0.5 * g * t^2
where:
- d is the distance fallen,
- g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth), and
- t is the time for which the object falls.
Given that the object is released from rest and falls for 1 second (t = 1 s), we can substitute these values into the equation to find the distance fallen:
d = 0.5 * 9.8 m/s^2 * (1 s)^2 = 4.9 m
So, the object falls 4.9 meters during the first second after release.
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