0.6 g of a coal sample with 92% C, 5% hydrogen, and 3% ash, caused a rise in the temperature of 2000 g water by 3.2 °C in a bomb calorimeter experiment. Calculate the GCV and NCV of coal, given. Water equivalent = 200 g. Ans:GCV= 11733.3 cal/g NCV= 11469.2 cal/g
Question
0.6 g of a coal sample with 92% C, 5% hydrogen, and 3% ash, caused a rise in the temperature of 2000 g water by 3.2 °C in a bomb calorimeter experiment. Calculate the GCV and NCV of coal, given. Water equivalent = 200 g. Ans:GCV= 11733.3 cal/g NCV= 11469.2 cal/g
Solution
To calculate the Gross Calorific Value (GCV) and Net Calorific Value (NCV) of the coal, we need to follow these steps:
-
First, we need to calculate the heat absorbed by the water and the bomb calorimeter. The heat absorbed (Q) can be calculated using the formula Q = m * c * ΔT, where m is the mass of the water, c is the specific heat capacity of water (1 cal/g°C), and ΔT is the change in temperature.
For the water: Q = 2000 g * 1 cal/g°C * 3.2 °C = 6400 cal For the bomb calorimeter: Q = 200 g * 1 cal/g°C * 3.2 °C = 640 cal
The total heat absorbed is therefore 6400 cal + 640 cal = 7040 cal.
-
The GCV of the coal can be calculated by dividing the total heat absorbed by the mass of the coal sample. So, GCV = 7040 cal / 0.6 g = 11733.3 cal/g.
-
To calculate the NCV, we need to subtract the heat of vaporization of the water formed during combustion from the GCV. The heat of vaporization is 9 cal/g for each gram of hydrogen in the coal.
The mass of hydrogen in the coal is 0.6 g * 5% = 0.03 g. So, the heat of vaporization is 0.03 g * 9 cal/g = 0.27 cal.
Therefore, NCV = GCV - heat of vaporization = 11733.3 cal/g - 0.27 cal/g = 11469.2 cal/g.
Similar Questions
One coal sample was analyzed and showed 90% C, 8% hydrogen, and 2% ash. 2.0 gof this coal sample was burned in a bomb calorimeter and the temperature of 2.5Kg water was increased from 25 to 35°C. Calculate the GCV and NCV of coal. Given:Water equivalents the instrument and the latent heat of vaporization are 1500 gand 580 cal/g, respectively.
Calculate the CV of a fuel sample of coal 0.6 g. Water equivalent of calorimeter 2200 g. Increase in temperature = 6.52 °C Ans:GCV= 23906 cal/g
2 kg of a coal sample was burnt in a bomb calorimeter. The heat liberated was estimated and found to be 14114 kcal. Calculate the calorific value of the coal sample.a.14114 kcal /kgb.7057 kcal/kgc.7057 cal/gd.14114 cal /g
Explain in detail with a suitable diagram how you will determine the GCV and NCVof a given coal sample.
Determine the water equivalent of the bomb calorimeter apparatus which gave the following data in an experiment: GCV of benzoic acid = 6324 cal/g Wt. of benzoic acid taken = 1.364 g Wt. of calorimeter = 1025 g Wt. of calorimeter + water = 3025 g Initial temperature = 11.872 C Final temperature = 14.625 C Cooling correction = 0.015 C Heat from fuses = 22 cals Washing of the bomb on analysis indicate the presence of 3.5 ml of N/10 HNO3 and there is no H2SO4formed.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.