A shop sells beef meals and chicken meals. On a certain day, they sell 500 meals in total. Each beef meal costs $5 and each chicken meal costs $4. At the end of the day, they notice that they have collected $2120 in revenue. How many chicken meals did they sell?
Question
A shop sells beef meals and chicken meals. On a certain day, they sell 500 meals in total. Each beef meal costs 4. At the end of the day, they notice that they have collected $2120 in revenue. How many chicken meals did they sell?
Solution
Let's denote the number of beef meals as B and the number of chicken meals as C.
From the problem, we have two equations:
-
B + C = 500 (since the total number of meals sold is 500)
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5B + 4C = 2120 (since each beef meal costs 4, and the total revenue is $2120)
We can solve these equations step by step:
Step 1: Multiply the first equation by 4, we get 4B + 4C = 2000.
Step 2: Subtract the new equation from the second equation, we get 5B + 4C - 4B - 4C = 2120 - 2000, which simplifies to B = 120.
Step 3: Substitute B = 120 into the first equation, we get 120 + C = 500, which simplifies to C = 500 - 120 = 380.
So, the shop sold 380 chicken meals.
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