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In the proton transfer step of a Friedel-Crafts alkylation reaction, where does the proton go?Select answer from the options belowTo the sigma complexTo the aluminum trichloride, restoring a proper valence shellTo the ring to restore aromaticityTo form an acid byproduct (HX)Save for LaterSubmit Answer

Question

In the proton transfer step of a Friedel-Crafts alkylation reaction, where does the proton go?Select answer from the options belowTo the sigma complexTo the aluminum trichloride, restoring a proper valence shellTo the ring to restore aromaticityTo form an acid byproduct (HX)Save for LaterSubmit Answer

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Solution

The proton goes to the aluminum trichloride, restoring a proper valence shell.

Similar Questions

What is the correct order of steps in the mechanism for a Friedel-Crafts alkylation (after the initial formation of the reactive electrophile, E+)?Select answer from the options belowProton Transfer: Nucleophilic Attack: Loss of a Leaving GroupNucleophilic Attack: Proton TransferProton Transfer: Nucleophilic AttackProton Transfer: Nucleophilic Attack: Proton Transfer

The mechanism for the alkylation of terminal alkynes involves which step?Select answer from the options belowNucleophilic AttackLoss of a Leaving GroupCarbocation rearrangementSave for LaterSubmit Answer

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The reaction given below is an example of Firedel craft  alkylation reaction.In number of cases of Friedel – crafts alkylation the final product is found to contain a rearranged alkyl group. Generally with stronger Lewis acid product is rearranged due to enough polariazation of complex while with weak Lewis acid no such effect is observed. Temperature also favoures rearranged product.What is electrophile in give reaction?

The general mechanism for an electrophilic aromatic substitution involves which steps?Select answer from the options belowStep 1: Proton TransferStep 2: Nucleophilic AttackStep 1: Nucleophilic AttackStep 2: Proton TransferStep 1: Nucleophilic AttackStep 2: RearrangementStep 3: Proton TransferStep 1: Nucleophilic AttackStep 2: RearrangementStep 3: Loss of a Leaving Group

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