In the school cafeteria, students choose their lunch from 3 sandwiches, 3 soups, 4 salads, and 2 drinks. How many different lunches are possible for a student who chooses exactly 1 sandwich, 1 soup, 1 salad, and 1 drink?Statistics Probability Combinations and Permutations
Question
In the school cafeteria, students choose their lunch from 3 sandwiches, 3 soups, 4 salads, and 2 drinks. How many different lunches are possible for a student who chooses exactly 1 sandwich, 1 soup, 1 salad, and 1 drink?Statistics Probability Combinations and Permutations
Solution
To find the number of different lunches possible for a student who chooses exactly 1 sandwich, 1 soup, 1 salad, and 1 drink, we can use the concept of combinations.
Step 1: Determine the number of choices for each category.
- There are 3 choices for sandwiches.
- There are 3 choices for soups.
- There are 4 choices for salads.
- There are 2 choices for drinks.
Step 2: Multiply the number of choices for each category.
- Multiply 3 choices for sandwiches by 3 choices for soups: 3 x 3 = 9.
- Multiply the result by 4 choices for salads: 9 x 4 = 36.
- Multiply the result by 2 choices for drinks: 36 x 2 = 72.
Therefore, there are 72 different lunches possible for a student who chooses exactly 1 sandwich, 1 soup, 1 salad, and 1 drink.
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