Let g(x) = xf(t) dt0, where f is the function whose graph is shown.(a) Evaluate g(0), g(2), g(4), g(6), and g(12).g(0) = g(2) = g(4) = g(6) = g(12) =

If F(x) = xf(t) dt2, where f is the function whose graph is given, which of the following values is largest?F(0)F(1)    F(2)F(3)F(4)

Video ExampleEXAMPLE 1 If f is the function whose graph is shown in the figure to the left and g(x) = xf(t) dt0, find the values of g(0), g(1), g(2), g(3), g(4), and g(5). Then sketch a rough graph of g.SOLUTION First, we notice that g(0) = 0f(t) dt0 = 0. From the figure below we see that g(1) is the area of the triangle:g(1) = 1f(t) dt0 = 12(1 · 2) = .To find g(2), we add to g(1) the area of the rectangle:g(2)  =  2f(t) dt0 =  1f(t) dt0 + 2f(t) dt1 =  1 +  =  .

the graph of F(x) = x0f(t) dt.(a) Explain why F(x) ≥ 0 on [0, 6].

Select the correct answer from each drop-down menu.Write the functions represented by the graphs.f(x) = g(x) = h(x) =

Choose which function is represented by the graph.A.𝑓(𝑥)=(𝑥−2)(𝑥+1)(𝑥+3)(𝑥+6)f(x)=(x−2)(x+1)(x+3)(x+6)B.𝑓(𝑥)=(𝑥−6)(𝑥−3)(𝑥−1)(𝑥+2)f(x)=(x−6)(x−3)(x−1)(x+2)C.𝑓(𝑥)=(𝑥−3)(𝑥−1)(𝑥−1)(𝑥+2)f(x)=(x−3)(x−1)(x−1)(x+2)D.𝑓(𝑥)=(𝑥−2)(𝑥+1)(𝑥+3)f(x)=(x−2)(x+1)(x+3)SUBMITarrow_backPREVIOUS