Give a complete and balanced equation for the reaction between methanoic acid $(\text{HCOOH})$(HCOOH) and sodium carbonate
Question
Give a complete and balanced equation for the reaction between methanoic acid (HCOOH) and sodium carbonate
Solution
The reaction between methanoic acid (HCOOH) and sodium carbonate (Na2CO3) is a double displacement reaction, also known as an acid-base reaction.
Here are the steps to write the balanced chemical equation:
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Write the unbalanced equation: HCOOH + Na2CO3 -> HCOONa + H2O + CO2
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Balance the equation: 2HCOOH + Na2CO3 -> 2HCOONa + H2O + CO2
So, the balanced chemical equation for the reaction between methanoic acid and sodium carbonate is:
2HCOOH + Na2CO3 -> 2HCOONa + H2O + CO2
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