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What will be the output of the following program?#include<stdio.h> int main() {     char j=1;     while(j < 5)     {         printf("%d, ", j);         j = j+1;     }     printf("\n");     return 0; }Select one:4, 3, 2, 11 2 3 42 3 4 5 61, 2, 3, 4,

Question

What will be the output of the following program?#include<stdio.h> int main() {     char j=1;     while(j < 5)     {         printf("%d, ", j);         j = j+1;     }     printf("\n");     return 0; }Select one:4, 3, 2, 11 2 3 42 3 4 5 61, 2, 3, 4,

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Solution

The output of the program will be "1, 2, 3, 4,".

Here's the step by step explanation:

  1. The program starts with the declaration of a character variable 'j' and assigns it a value of 1.

  2. Then it enters a while loop which will continue to execute as long as the value of 'j' is less than 5.

  3. Inside the loop, it first prints the current value of 'j', followed by a comma and a space.

  4. Then it increments the value of 'j' by 1.

  5. This process repeats until 'j' is no longer less than 5 (i.e., when 'j' becomes 5), at which point the loop terminates.

  6. Finally, it prints a newline character and the program ends.

So, the output will be the sequence of numbers 1, 2, 3, 4 each followed by a comma and a space, and then a newline.

This problem has been solved

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