What will be the output of the following program?#include<stdio.h> int main() { char j=1; while(j < 5) { printf("%d, ", j); j = j+1; } printf("\n"); return 0; }Select one:4, 3, 2, 11 2 3 42 3 4 5 61, 2, 3, 4,
Question
What will be the output of the following program?#include<stdio.h> int main() { char j=1; while(j < 5) { printf("%d, ", j); j = j+1; } printf("\n"); return 0; }Select one:4, 3, 2, 11 2 3 42 3 4 5 61, 2, 3, 4,
Solution
The output of the program will be "1, 2, 3, 4,".
Here's the step by step explanation:
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The program starts with the declaration of a character variable 'j' and assigns it a value of 1.
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Then it enters a while loop which will continue to execute as long as the value of 'j' is less than 5.
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Inside the loop, it first prints the current value of 'j', followed by a comma and a space.
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Then it increments the value of 'j' by 1.
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This process repeats until 'j' is no longer less than 5 (i.e., when 'j' becomes 5), at which point the loop terminates.
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Finally, it prints a newline character and the program ends.
So, the output will be the sequence of numbers 1, 2, 3, 4 each followed by a comma and a space, and then a newline.
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