Re-write the quadratic function below in Standard Formy, equals, 5, left bracket, x, minus, 2, right bracket, squared, minus, 4y=5(x−2) 2 −4
Question
Re-write the quadratic function below in Standard Formy, equals, 5, left bracket, x, minus, 2, right bracket, squared, minus, 4y=5(x−2) 2 −4
Solution
The quadratic function y = 5(x - 2)^2 - 4 can be rewritten in standard form by expanding the squared term and simplifying the equation. Here are the steps:
- Expand the squared term: y = 5(x^2 - 4x + 4) - 4
- Distribute the 5: y = 5x^2 - 20x + 20 - 4
- Simplify the constant terms: y = 5x^2 - 20x + 16
So, the standard form of the given quadratic function is y = 5x^2 - 20x + 16.
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