Select the correct answerA is 50% more efficient than B and C is 40% less efficient than B. Working together, they can complete a task in 10 days. In how many days will A alone complete 150% of that task?Options35312811
Question
Select the correct answerA is 50% more efficient than B and C is 40% less efficient than B. Working together, they can complete a task in 10 days. In how many days will A alone complete 150% of that task?Options35312811
Solution
To solve this problem, we need to follow these steps:
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Let's assume the efficiency of B is 100 units. Then, A's efficiency is 150 units (50% more than B) and C's efficiency is 60 units (40% less than B).
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The total efficiency of A, B, and C working together is 150 + 100 + 60 = 310 units.
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If they can complete a task in 10 days, then the total work is 310 units/day * 10 days = 3100 units.
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If A needs to complete 150% of the task, the total work becomes 3100 units * 150% = 4650 units.
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To find out how many days A alone will complete 150% of the task, we divide the total work by A's efficiency: 4650 units / 150 units/day = 31 days.
So, the correct answer is 31 days.
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