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RS.5625 is divided among A, B and C so that A may receive ½ as much as B and C together receive and B receive ¼ of what A and C together receive. The share of A is more than that of B by:OptionsRS.1600RS.775RS.750RS.1500RS.700

Question

RS.5625 is divided among A, B and C so that A may receive ½ as much as B and C together receive and B receive ¼ of what A and C together receive. The share of A is more than that of B by:OptionsRS.1600RS.775RS.750RS.1500RS.700

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Solution

Let's solve this step by step:

  1. Let's assume the share of A as 'x'. According to the problem, A receives 1/2 of what B and C receive together. So, B + C = 2x.

  2. It's also mentioned that B receives 1/4 of what A and C receive together. So, B = 1/4(A + C). Substituting C = 2x - B in this equation, we get B = 1/4(A + 2x - B). Solving this, we get B = x/3.

  3. Now, we know that A + B + C = Rs.5625. Substituting B = x/3 and C = 2x - B in this equation, we get x + x/3 + 2x - x/3 = 5625. Solving this, we get x = Rs.2250. So, A's share is Rs.2250.

  4. B's share is x/3 = 2250/3 = Rs.750.

  5. Therefore, the share of A is more than that of B by Rs.2250 - Rs.750 = Rs.1500.

So, the correct option is RS.1500.

This problem has been solved

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