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A coil having n turns and resistance RΩ is connected with a galvanometer of resistance 4RΩ. This combination is moved in time t seconds from a magnetic field W1 weber to W2 weber. The induced current in the circuit is

Question

A coil having n turns and resistance RΩ is connected with a galvanometer of resistance 4RΩ. This combination is moved in time t seconds from a magnetic field W1 weber to W2 weber. The induced current in the circuit is

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Solution

The induced current in the circuit can be calculated using Faraday's law of electromagnetic induction, which states that the induced electromotive force (EMF) in a circuit is equal to the rate of change of magnetic flux through the circuit.

The magnetic flux (Φ) is given by the equation Φ = BA, where B is the magnetic field strength and A is the area of the coil. In this case, the change in magnetic flux (ΔΦ) is given by the difference in the magnetic fields (W2 - W1).

The induced EMF (ε) is then given by the equation ε = -n * ΔΦ / Δt, where n is the number of turns in the coil and Δt is the change in time. The negative sign indicates that the induced EMF will act to oppose the change in magnetic flux, as per Lenz's law.

The induced current (I) can then be calculated using Ohm's law, which states that the current is equal to the voltage (in this case, the induced EMF) divided by the resistance. The total resistance in the circuit is the sum of the resistance of the coil (R) and the resistance of the galvanometer (4R), which is 5R.

So, the induced current is given by the equation I = ε / R_total = -n * ΔΦ / (Δt * 5R) = -n * (W2 - W1) / (5Rt).

This is the step-by-step process to calculate the induced current in the circuit.

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