Consider two identical waves (both with a wavelength of 22 m) emitted in phase arriving at a point from two sources such that one of the waves has travelled 55 m more than the other. How do the two waves combine at this point?A. Perfectly ConstructivelyB. Perfectly DestructivelyC. Partially constructively/destructivelyEnter the letter of your choice

To answer this question, we need to understand the concept of wave interference, which is the phenomenon that occurs when two waves meet while they are traveling along the same medium.

The key point here is that one of the waves has travelled 55 m more than the other. We need to determine how many wavelengths this distance represents, because this will tell us the phase difference between the two waves when they combine.

The wavelength of the waves is given as 22 m. So, we divide the extra distance travelled by one wave (55 m) by the wavelength (22 m):

55 m / 22 m = 2.5 wavelengths

This means that the waves are half a wavelength out of phase when they combine, because the 0.5 represents half a wavelength.

When waves are half a wavelength out of phase, they combine destructively. This is because the peak of one wave aligns with the trough of the other, and vice versa, so they cancel each other out.

Therefore, the answer is B. Perfectly Destructively.