A bus accelerates uniformly from 54 km/h to 72 km/h in 10 seconds Calculate(i) acceleration in m/s2(ii) distance covered by the bus in meters during this interval

(i) Acceleration:

First, we need to convert the speeds from km/h to m/s because the standard unit of acceleration is m/s².

1 km/h = 1000 m/3600 s = 0.27778 m/s

So, 54 km/h = 54 * 0.27778 = 15 m/s And, 72 km/h = 72 * 0.27778 = 20 m/s

Acceleration is defined as the change in velocity over time. So, we can calculate it using the formula:

a = (v_f - v_i) / t

where: v_f = final velocity = 20 m/s v_i = initial velocity = 15 m/s t = time = 10 s

Substituting these values into the formula, we get:

a = (20 m/s - 15 m/s) / 10 s = 0.5 m/s²

(ii) Distance:

The formula to calculate the distance covered by an object moving with uniform acceleration is:

d = v_it + 0.5a*t²

where: v_i = initial velocity = 15 m/s a = acceleration = 0.5 m/s² t = time = 10 s

Substituting these values into the formula, we get:

d = 15 m/s * 10 s + 0.5 * 0.5 m/s² * (10 s)² = 150 m + 25 m = 175 m

So, the bus covered a distance of 175 meters during this interval.