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What is the output of the following code:person = {'name': 'Phill', 'age': 22}a = person. setdefault('age')print('person = ', persons)print('Age = ', a)Aperson = {'name': 'Phill'} and Age = 22Bperson = {'name': 'Phill', 'age': 22} and Age = 22Cperson = {'age': 22} and Age = 22Dperson = {'name': 'Phill', 'age': 22} and name = Phil

Question

What is the output of the following code:person = {'name': 'Phill', 'age': 22}a = person. setdefault('age')print('person = ', persons)print('Age = ', a)Aperson = {'name': 'Phill'} and Age = 22Bperson = {'name': 'Phill', 'age': 22} and Age = 22Cperson = {'age': 22} and Age = 22Dperson = {'name': 'Phill', 'age': 22} and name = Phil

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Solution 1

The output of the given code will be:

Bperson = {'name': 'Phill', 'age': 22} and Age = 22

Here's the step by step explanation:

  1. A dictionary named 'person' is created with 'name' and 'age' as keys and 'Phill' and 22 as their respective values.

  2. The setdefault() method is a built-in Python method that returns the value of a key (if the key is in dictionary). If not, it inserts key with a value to the dictionary. In this case, 'age' is already a key in the dictionary, so it will return its value, which is 22. This value is stored in the variable 'a'.

  3. When you print 'person', it will output the original dictionary because the setdefault() method did not change anything (as 'age' was already a key in the dictionary).

  4. When you print 'a', it will output the value returned by the setdefault() method, which is 22.

So, the output will be the dictionary 'person' and the value of 'a', which is 22.

This problem has been solved

Solution 2

The output of the given code will be:

Bperson = {'name': 'Phill', 'age': 22} and Age = 22

Here's the step by step explanation:

  1. A dictionary named 'person' is created with two key-value pairs: 'name' set to 'Phill' and 'age' set to 22.

  2. The setdefault() method is called on the 'person' dictionary with 'age' as the argument. This method returns the value of the specified key if the key is in the dictionary. If not, it inserts the key with a value of None. In this case, 'age' is already a key in the dictionary, so its value 22 is returned and assigned to 'a'.

  3. The 'person' dictionary is printed, which remains unchanged as {'name': 'Phill', 'age': 22}.

  4. The value of 'a' is printed, which is 22.

So, the output is Bperson = {'name': 'Phill', 'age': 22} and Age = 22.

This problem has been solved

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