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The equation, y = 5 sin (3t – 4x), where y is in millimeters, x is in metres and t is in seconds represents a wave motion. Determine the wave’s velocity of propagation.*1 point0.50 m/s0.75 m/s1.0 m/s1.2 m/s

Question

The equation, y = 5 sin (3t – 4x), where y is in millimeters, x is in metres and t is in seconds represents a wave motion. Determine the wave’s velocity of propagation.*1 point0.50 m/s0.75 m/s1.0 m/s1.2 m/s

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Solution 1

The velocity of a wave is given by the formula v = ω/k, where ω is the angular frequency and k is the wave number.

From the given wave equation, y = 5 sin (3t – 4x), we can identify the values of ω and k.

The coefficient of t (time) is the angular frequency ω. So, ω = 3 rad/s.

The coefficient of x (distance) is the wave number k. So, k = 4 rad/m.

Now, we can substitute these values into the formula for velocity:

v = ω/k = 3 rad/s / 4 rad/m = 0.75 m/s.

So, the wave's velocity of propagation is 0.75 m/s.

This problem has been solved

Solution 2

The velocity of a wave is given by the formula v = ω/k, where ω is the angular frequency and k is the wave number.

From the given wave equation, y = 5 sin (3t – 4x), we can identify that ω = 3 (from the coefficient of t) and k = 4 (from the coefficient of x).

Substituting these values into the formula, we get:

v = ω/k = 3/4 = 0.75 m/s

So, the velocity of propagation of the wave is 0.75 m/s.

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