Find the 60th term of the following arithmetic sequence.5,  14,  23,  32,

The given sequence is an arithmetic sequence. In an arithmetic sequence, the difference between any two successive members is a constant. This constant difference is also called the "common difference".

The common difference (d) can be found by subtracting the first term from the second term.

d = 14 - 5 = 9

The nth term (Tn) of an arithmetic sequence can be found using the formula:

Tn = a + (n - 1) * d

where:

• Tn is the nth term
• a is the first term in the sequence
• n is the position of the term in the sequence
• d is the common difference

We are asked to find the 60th term, so n = 60. The first term a = 5, and the common difference d = 9.

Substituting these values into the formula, we get:

T60 = 5 + (60 - 1) * 9 T60 = 5 + 59 * 9 T60 = 5 + 531 T60 = 536

So, the 60th term of the given arithmetic sequence is 536.