You're writing a Bash script to process a list of filenames stored in a file, and for each file, you need to extract the base filename (without the path or extension). Which command correctly extracts the base filename for each line in the file?0.5 Markscat filenames.txt | xargs -I{} basename {} | echofor filename in $(cat filenames.txt); doecho "$(basename $filename)"donewhile read line; dofilename=$(basename "$line")echo "$filename"done < filenames.txtfind . -type f -exec basename {} \; | cat > filenames.txtfor line in $(cat filenames.txt); dofilename=$(basename $line)echo "$filename"done

Question

You're writing a Bash script to process a list of filenames stored in a file, and for each file, you need to extract the base filename (without the path or extension). Which command correctly extracts the base filename for each line in the file?0.5 Markscat filenames.txt | xargs -I{} basename {} | echofor filename in $(cat filenames.txt); doecho "$ (basename $filename)"donewhile read line; dofilename=$ (basename " $line")echo "$ filename"done < filenames.txtfind . -type f -exec basename {} ; | cat > filenames.txtfor line in $(cat filenames.txt); dofilename=$ (basename $line)echo "$ filename"done

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Solution

The correct command to extract the base filename for each line in the file is:

while read line; do
filename=$(basename "$line")
echo "$filename"
done < filenames.txt

This command reads each line from the file filenames.txt, assigns it to the variable line, then uses the basename command to extract the base filename from the full path stored in line. The result is then echoed (printed) out. This process is repeated for each line in the file.

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