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Use the given matrices to evaluate the expression.$A=\begin{bmatrix}4&1\\-3&0\end{bmatrix}$A=[4 1−3 0]​ ,  $B=\begin{bmatrix}5&-2\\6&-1\end{bmatrix}$B=[5 −26 −1]​ ,  $C=\begin{bmatrix}1&0\\0&\ \ 1\end{bmatrix}$C=[1 00 1]​$AC+BC=$AC+BC=​

Question

Use the given matrices to evaluate the expression.A=[4130]A=\begin{bmatrix}4&1\\-3&0\end{bmatrix}A=[4 1−3 0]​ ,  B=[5261]B=\begin{bmatrix}5&-2\\6&-1\end{bmatrix}B=[5 −26 −1]​ ,  C=[100  1]C=\begin{bmatrix}1&0\\0&\ \ 1\end{bmatrix}C=[1 00 1]​AC+BC=AC+BC=AC+BC=​

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Solution

To evaluate the expression AC + BC, we first need to find the products AC and BC.

Matrix multiplication is done element by element, with the element in the i-th row and j-th column of the product being the sum of the product of the corresponding elements in the i-th row of the first matrix and the j-th column of the second matrix.

  1. Calculate AC:

A = [4 1; -3 0], C = [1 0; 0 1]

AC = [41 + 10, 40 + 11; -31 + 00, -30 + 01] = [4, 1; -3, 0]

  1. Calculate BC:

B = [5 -2; 6 -1], C = [1 0; 0 1]

BC = [51 + -20, 50 + -21; 61 + -10, 60 + -11] = [5, -2; 6, -1]

  1. Now, add the two resulting matrices (AC + BC):

AC + BC = [4 + 5, 1 + -2; -3 + 6, 0 + -1] = [9, -1; 3, -1]

So, AC + BC = [9 -1; 3 -1].

This problem has been solved

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