What will be the output of the following Java program? class scopevariable { public static void main(String args[]) { int c; c = 15; { int d = 36; System.out.print(c + " " + d); } System.out.println(c + " " + d); } }Options5 6 55 6 5 6Runtime errorCompilation error
Question
What will be the output of the following Java program? class scopevariable { public static void main(String args[]) { int c; c = 15; { int d = 36; System.out.print(c + " " + d); } System.out.println(c + " " + d); } }Options5 6 55 6 5 6Runtime errorCompilation error
Solution
The output of the Java program will be a Compilation error. This is because the variable 'd' is declared inside a block and its scope is limited to that block only. When we try to access 'd' outside of its scope (in the last print statement), the compiler doesn't recognize 'd' and throws a compilation error.
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