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The scalar product of 5i + j – 3k and 3i – 4j + 7k is....A15B-15C10D-10

Question

The scalar product of 5i + j – 3k and 3i – 4j + 7k is....A15B-15C10D-10

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Solution

To find the scalar product (also known as the dot product) of two vectors, you multiply their corresponding components and then sum the results. Let's denote the vectors as A and B:

A = 5i + j - 3k
B = 3i - 4j + 7k

The dot product A · B is calculated as follows:

  1. Multiply the i-components:
    5×3=15 5 \times 3 = 15

  2. Multiply the j-components:
    1×(4)=4 1 \times (-4) = -4

  3. Multiply the k-components:
    3×7=21 -3 \times 7 = -21

  4. Sum these products:
    15+(4)+(21)=15421=10 15 + (-4) + (-21) = 15 - 4 - 21 = -10

So, the scalar product of the vectors A and B is -10.

Therefore, the correct answer is D) -10.

This problem has been solved

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