Consider the following table Employee.Select the output returned by the following query: SELECT branch AS department, AVG(age) AS average_ageFROM employeeGROUP BY branchHAVING COUNT(*) >= 2ORDER BY average_age DESC;
Question
Consider the following table Employee.Select the output returned by the following query: SELECT branch AS department, AVG(age) AS average_ageFROM employeeGROUP BY branchHAVING COUNT(*) >= 2ORDER BY average_age DESC;
Solution
Without the actual data from the Employee table, I can't provide the exact output. However, I can explain what the SQL query does.
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SELECT branch AS department, AVG(age) AS average_age: This part of the query selects the 'branch' column and renames it as 'department'. It also calculates the average age of employees in each branch. -
FROM employee: This specifies the table from which the data is being selected, which is the 'employee' table. -
GROUP BY branch: This groups the selected data by the 'branch' column. This means that the output will have one row for each unique value in the 'branch' column. -
HAVING COUNT(*) >= 2: This filters the grouped data to only include groups that have 2 or more rows. In other words, it only includes branches that have 2 or more employees. -
ORDER BY average_age DESC: This sorts the output rows by the 'average_age' column in descending order.
So, the output of this query will be a table with two columns: 'department' and 'average_age'. Each row will represent a branch from the 'employee' table that has 2 or more employees, and the rows will be sorted by the average age of employees in each branch, from highest to lowest.
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