Recall that with the CSMA/CD protocol, the adapter waits K*512 bit times after a collision, where K is drawn randomly. For K = 100, how long does the adapter wait until returning to Step 2 for a 10 Mbps broadcast channel? For a 100 Mbps broadcast channel?

To calculate the waiting time for the adapter to return to Step 2 after a collision using the CSMA/CD protocol, we need to consider the value of K and the bit rate of the broadcast channel.

For a 10 Mbps broadcast channel, the adapter waits K*512 bit times after a collision. Given that K = 100, we can calculate the waiting time as follows:

Waiting time = K * 512 bit times = 100 * 512 bit times = 51,200 bit times

To convert the waiting time to seconds, we divide it by the bit rate of the channel:

Waiting time (in seconds) = Waiting time (in bit times) / Bit rate = 51,200 bit times / 10 Mbps = 5,120 microseconds

Therefore, for a 10 Mbps broadcast channel and K = 100, the adapter waits 5,120 microseconds until returning to Step 2 after a collision.

Similarly, for a 100 Mbps broadcast channel, we can use the same formula:

Waiting time = K * 512 bit times = 100 * 512 bit times = 51,200 bit times

Waiting time (in seconds) = Waiting time (in bit times) / Bit rate = 51,200 bit times / 100 Mbps = 512 microseconds

Hence, for a 100 Mbps broadcast channel and K = 100, the adapter waits 512 microseconds until returning to Step 2 after a collision.