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The mean of the ages of five friends is 16 years. If three of them are of the same age and theother two are of 14 and 18 years, then the age of each friends having the same age isA. 12 years.B. 16 years.C. 18 years.D. 20 years

Question

The mean of the ages of five friends is 16 years. If three of them are of the same age and theother two are of 14 and 18 years, then the age of each friends having the same age isA. 12 years.B. 16 years.C. 18 years.D. 20 years

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Solution

To solve this problem, we first need to understand that the mean is calculated by adding all the values together and then dividing by the number of values.

Step 1: We know that the mean age of the five friends is 16 years. So, the total age of the five friends is 16 years * 5 = 80 years.

Step 2: We also know that two of the friends are 14 and 18 years old. So, the combined age of these two friends is 14 years + 18 years = 32 years.

Step 3: To find the total age of the three friends who are the same age, we subtract the combined age of the two friends from the total age of all five friends. So, 80 years - 32 years = 48 years.

Step 4: Since the three friends are the same age, we divide the total age of these three friends by 3 to find the age of each friend. So, 48 years / 3 = 16 years.

So, each of the three friends is 16 years old. The answer is B. 16 years.

This problem has been solved

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