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A bead can slide on a smooth wire and particle of mass m is attached to the bead by a light string of length L. The particle is held in contact with the wire with the string taut and is then let fall. The bead has mass 3 m.Vertical component of velocity of mass m, when the string makes angle  30o  with wire will be

Question

A bead can slide on a smooth wire and particle of mass m is attached to the bead by a light string of length L. The particle is held in contact with the wire with the string taut and is then let fall. The bead has mass 3 m.Vertical component of velocity of mass m, when the string makes angle  30o  with wire will be

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Solution

This problem involves the conservation of energy. Initially, the system has potential energy due to the height of the mass m. As the mass falls, this potential energy is converted into kinetic energy.

Step 1: Identify the initial potential energy of the system. The initial height of the mass m is L (the length of the string). So, the initial potential energy (PE_initial) is mgL, where g is the acceleration due to gravity.

Step 2: Identify the final potential energy of the system. When the string makes an angle of 30 degrees with the wire, the height of the mass m is Lcos(30). So, the final potential energy (PE_final) is mgLcos(30).

Step 3: Identify the change in potential energy. The change in potential energy (ΔPE) is PE_initial - PE_final = mgL - mgL*cos(30).

Step 4: Apply the conservation of energy. The change in potential energy is equal to the change in kinetic energy. The kinetic energy of the system is shared between the bead and the mass m. The bead has mass 3m and the mass m has mass m. So, the final kinetic energy (KE_final) is (1/2)3mv^2 + (1/2)mv^2, where v is the velocity of the bead and the mass m.

Step 5: Solve for v. Set ΔPE = KE_final and solve for v.

Note: The vertical component of the velocity is v*sin(30).

This problem has been solved

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