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Suppose that we have an ordered array and we want to do the binary search on it. If we know that the best-case efficiency is 1 comparison, and the worst-case efficiency is 11 comparisons, can we say that the average-case efficiency is 6 comparisons (from (1 + 11)/2)?Group of answer choicesyesno

Question

Suppose that we have an ordered array and we want to do the binary search on it. If we know that the best-case efficiency is 1 comparison, and the worst-case efficiency is 11 comparisons, can we say that the average-case efficiency is 6 comparisons (from (1 + 11)/2)?Group of answer choicesyesno

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Solution

No, we cannot say that the average-case efficiency is 6 comparisons. The average-case efficiency of a binary search is not simply the average of the best and worst case. It is determined by the probability of each possible number of comparisons, which in a binary search is not a uniform distribution. Therefore, the average-case efficiency could be less than, equal to, or greater than 6, depending on the specific probabilities.

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