Sure, let's factorise the given expression 81x^2 - 121y^2.

Step 1: Recognise the given expression as a difference of squares. The difference of squares is a term used in algebra to describe the expression a^2 - b^2, which can be factored into (a - b)(a + b).

Step 2: Write down the square roots of both terms. The square root of 81x^2 is 9x and the square root of 121y^2 is 11y.

Step 3: Substitute these values into the difference of squares formula. So, 81x^2 - 121y^2 = (9x - 11y)(9x + 11y).

So, the factorised form of 81x^2 - 121y^2 is (9x - 11y)(9x + 11y).

Question

Sure, let's factorise the given expression 81x^2 - 121y^2.

Step 1: Recognise the given expression as a difference of squares. The difference of squares is a term used in algebra to describe the expression a^2 - b^2, which can be factored into (a - b)(a + b).

Step 2: Write down the square roots of both terms. The square root of 81x^2 is 9x and the square root of 121y^2 is 11y.

Step 3: Substitute these values into the difference of squares formula. So, 81x^2 - 121y^2 = (9x - 11y)(9x + 11y).

So, the factorised form of 81x^2 - 121y^2 is (9x - 11y)(9x + 11y).

Knowee AI · Accepted Answer

Sure, let's factorise the given expression 81x^2 - 121y^2.

Step 1: Recognise the given expression as a difference of squares. The difference of squares is a term used in algebra to describe the expression a^2 - b^2, which can be factored into (a - b)(a + b).

Step 2: Write down the square roots of both terms. The square root of 81x^2 is 9x and the square root of 121y^2 is 11y.

Step 3: Substitute these values into the difference of squares formula. So, 81x^2 - 121y^2 = (9x - 11y)(9x + 11y).

So, the factorised form of 81x^2 - 121y^2 is (9x - 11y)(9x + 11y).

Factorise 81x2−121y2 completely.

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