The reaction between HCl and KMnO4 in an acidic medium gives the following half reactions.Oxidation half reaction: 2Cl(aq)− → Cl2(g)Reduction half reaction: MnO4(aq)− → Mn(aq)2+What should be added on the left hand side (L.H.S.) and the right hand side (R.H.S.) of theequation to balance the reduction half reaction?
Question
The reaction between HCl and KMnO4 in an acidic medium gives the following half reactions.Oxidation half reaction: 2Cl(aq)− → Cl2(g)Reduction half reaction: MnO4(aq)− → Mn(aq)2+What should be added on the left hand side (L.H.S.) and the right hand side (R.H.S.) of theequation to balance the reduction half reaction?
Solution
To balance the reduction half reaction, we need to balance the atoms and charges by adding water molecules (H2O) and hydrogen ions (H+).
Step 1: Balance the Mn atoms MnO4- → Mn2+
Step 2: Balance the O atoms by adding H2O on the right side MnO4- → Mn2+ + 4H2O
Step 3: Balance the H atoms by adding H+ on the left side MnO4- + 8H+ → Mn2+ + 4H2O
Step 4: Balance the charges by adding electrons (e-) on the right side MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
So, to balance the reduction half reaction, we should add 8H+ on the L.H.S. and 4H2O and 5e- on the R.H.S.
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