A factory produces a type of light tube, Its lifespan can be expressed this way: X~(u, 200^2). From experience, it's known that the average lifespan u is 1500 hours. Now, after adopting a new technique, 25 light tubes are randomly selected from those produced and the average lifespan is found to be 1675 hours. With the new technique adopted, what is the value of the test statistic?
Question
A factory produces a type of light tube, Its lifespan can be expressed this way: X~(u, 200^2). From experience, it's known that the average lifespan u is 1500 hours. Now, after adopting a new technique, 25 light tubes are randomly selected from those produced and the average lifespan is found to be 1675 hours. With the new technique adopted, what is the value of the test statistic?
Solution
The test statistic in this case can be calculated using the formula for a z-score, which is:
Z = (X - μ) / (σ / √n)
where:
- X is the sample mean
- μ is the population mean
- σ is the population standard deviation
- n is the sample size
In this case, we have:
- X = 1675 hours (the sample mean)
- μ = 1500 hours (the population mean)
- σ = 200 hours (the population standard deviation)
- n = 25 (the sample size)
Plugging these values into the formula, we get:
Z = (1675 - 1500) / (200 / √25) = 175 / (200 / 5) = 175 / 40 = 4.375
So, the value of the test statistic is 4.375.
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