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Accept a sequence of words as input. Create a dictionary named real_dict whose keys are the letters of the English alphabet. For each key (letter), the corresponding value should be a list of words that begin with this key (letter). For any given key, the words should be appended to the corresponding list in the order in which they appear in the sequence. You can assume that all words of the sequence will be in lower case.You do not have to print the output to the console.

Question

Accept a sequence of words as input. Create a dictionary named real_dict whose keys are the letters of the English alphabet. For each key (letter), the corresponding value should be a list of words that begin with this key (letter). For any given key, the words should be appended to the corresponding list in the order in which they appear in the sequence. You can assume that all words of the sequence will be in lower case.You do not have to print the output to the console.

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Solution

Here is a step-by-step Python solution for the problem:

  1. Initialize an empty dictionary named real_dict. In Python, you can do this by writing real_dict = {}.

  2. Accept a sequence of words as input. You can do this using the input() function in Python, which reads a line of text from the user. Since we want a sequence of words, we can split the input line into words using the split() function. Here is how you can do it: words = input().split().

  3. Now, we need to iterate over each word in the sequence. In Python, you can do this using a for loop. Here is how you can do it: for word in words:.

  4. For each word, we need to get the first letter. In Python, you can get the first character of a string s by writing s[0].

  5. We need to check if this letter is already a key in real_dict. In Python, you can check if a key k is in a dictionary d by writing k in d.

  6. If the letter is not a key in real_dict, we need to add it and associate it with a list that contains the current word. In Python, you can add a key-value pair to a dictionary d by writing d[k] = v.

  7. If the letter is already a key in real_dict, we need to append the current word to the list associated with this key. In Python, you can append an element e to a list l by writing l.append(e).

Here is the complete Python code that implements these steps:

real_dict = {}
words = input().split()
for word in words:
    first_letter = word[0]
    if first_letter not in real_dict:
        real_dict[first_letter] = [word]
    else:
        real_dict[first_letter].append(word)

This code does not print the output to the console, as specified in the problem statement.

This problem has been solved

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