What will be the output of the following program?#include <iostream>using namespace std;int main()    {      int x, y;      x = 5;      x++ * ++x;      cout <<x << " " <<y;      return 0;    }Select one:307  06  0Compilation error36

The output of the program will be "7 0". Here's the step-by-step explanation:

1. The program starts with the inclusion of the iostream library which allows it to perform input and output operations.

2. The namespace std is declared to avoid the need to use std:: before standard functions like cout and cin.

3. The main function is declared. This is the function that is executed when the program runs.

4. Two integer variables, x and y, are declared.

5. The variable x is assigned the value 5.

6. The expression x++ * ++x is evaluated. This involves two operations: post-increment (x++) and pre-increment (++x). The post-increment operation increases the value of x by 1 after its current value is used in the expression, while the pre-increment operation increases the value of x by 1 before it is used in the expression. However, the result of this expression is not assigned to any variable, so it has no effect on the program.

7. The value of x, which is now 7 due to the increment operations, and the value of y, which is 0 because it has not been assigned a value, are printed to the console.

8. The program returns 0, indicating successful execution.