A marketing company runs a web campaign that includes running an ad on the common platforms. There are an average of 4.7 ad clicks per hour.Use the Poisson distribution to find the probability that 3 or more ad clicks occur in a given hour.Do not round intermediate computations, and round your answer to three decimal places.(If necessary, consult a list of formulas.)

The Poisson distribution is a probability distribution that can be used to model the number of events (in this case, ad clicks) that occur within a fixed interval of time (in this case, an hour). The formula for the Poisson distribution is:

P(X=k) = (λ^k * e^-λ) / k!

where:

• P(X=k) is the probability of k events occurring in an interval,
• λ is the average rate of value (in this case, 4.7 ad clicks per hour),
• e is the base of the natural logarithm (approximately equal to 2.71828),
• k! is the factorial of k.

We want to find the probability that 3 or more ad clicks occur in a given hour. This is equivalent to finding 1 minus the probability that fewer than 3 ad clicks occur. So we need to calculate P(X<3) and subtract it from 1.

P(X<3) = P(X=0) + P(X=1) + P(X=2)

We can calculate these probabilities using the Poisson formula:

P(X=0) = (4.7^0 * e^-4.7) / 0! = e^-4.7 P(X=1) = (4.7^1 * e^-4.7) / 1! = 4.7 * e^-4.7 P(X=2) = (4.7^2 * e^-4.7) / 2! = (4.7^2 / 2) * e^-4.7

Adding these up gives us P(X<3). Subtracting this from 1 gives us the probability that 3 or more ad clicks occur in a given hour.

Remember to round your final answer to three decimal places.

The Poisson distribution is a probability distribution that can be used to model the number of events (in this case, ad clicks) that occur within a fixed interval of time (in this case, an hour). The formula for the Poisson distribution is:

P(X=k) = (λ^k * e^-λ) / k!

where:

• P(X=k) is the probability of k events occurring in an interval,
• λ is the average rate of value (in this case, 4.7 ad clicks per hour),
• e is the base of the natural logarithm (approximately equal to 2.71828),
• k! is the factorial of k.

We want to find the probability that 3 or more ad clicks occur in a given hour. This is equivalent to finding 1 minus the probability that fewer than 3 ad clicks occur. So we need to calculate P(X<3) and subtract it from 1.

P(X<3) = P(X=0) + P(X=1) + P(X=2)

We can calculate these probabilities using the Poisson formula:

P(X=0) = (4.7^0 * e^-4.7) / 0! = e^-4.7 P(X=1) = (4.7^1 * e^-4.7) / 1! = 4.7 * e^-4.7 P(X=2) = (4.7^2 * e^-4.7) / 2! = 4.7^2 * e^-4.7 / 2

Adding these up gives us P(X<3). Subtracting this from 1 gives us the probability that 3 or more ad clicks occur in a given hour.

Remember to round your final answer to three decimal places.