A block of relative density 0.4 is submerged inside water and it is attached to bottom of container by a string. If mass of the block is 2 kg the tension in string is ________ (g = 10m/s2)
Question
A block of relative density 0.4 is submerged inside water and it is attached to bottom of container by a string. If mass of the block is 2 kg the tension in string is ________ (g = 10m/s2)
Solution
The tension in the string can be calculated using the formula for buoyant force, which is the difference between the weight of the object in air and the weight of the object in water.
Step 1: Calculate the weight of the block in air. This is given by the formula Weight = mass * gravity. So, Weight = 2 kg * 10 m/s^2 = 20 N.
Step 2: Calculate the weight of the block in water. The relative density (or specific gravity) of an object is the ratio of the density of the object to the density of water. Since the relative density of the block is 0.4, this means the block is 0.4 times as dense as water. Therefore, the weight of the block in water is 0.4 times its weight in air. So, Weight in water = 0.4 * 20 N = 8 N.
Step 3: Calculate the buoyant force. This is the difference between the weight of the block in air and the weight of the block in water. So, Buoyant force = 20 N - 8 N = 12 N.
Step 4: The tension in the string is equal to the buoyant force, because the string is holding the block against the buoyant force trying to lift it up. So, the tension in the string is 12 N.
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