Factoring trinomials: 𝑥 2 + 𝑏 𝑥 + 𝑐 = ( 𝑥 + 𝑝 ) ( 𝑥 + 𝑞 ) x 2 +bx+c=(x+p)(x+q)
Question
Factoring trinomials: 𝑥 2 + 𝑏 𝑥 + 𝑐
( 𝑥 + 𝑝 ) ( 𝑥 + 𝑞 ) x 2 +bx+c=(x+p)(x+q)
Solution
To factor a trinomial of the form x^2 + bx + c, you need to find two numbers p and q such that:
- p * q = c (The product of p and q is equal to c, the constant term)
- p + q = b (The sum of p and q is equal to b, the coefficient of the middle term)
Here are the steps to do this:
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Write down the trinomial equation x^2 + bx + c.
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Identify the coefficients b and c in the equation.
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List all the factor pairs of c (the constant term).
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From this list, find the pair of factors that add up to b (the coefficient of the middle term).
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Once you have found the correct pair of factors, rewrite the middle term of the trinomial as the sum of the terms bx and cx.
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Factor by grouping. Split the middle term bx into the sum of two terms, ax and cx, and group the terms to get (x^2 + ax) + (cx + c).
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Factor out the greatest common factor from each group.
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If factored correctly, you should now have two binomial factors of the form (x + p)(x + q), where p and q are the factors you found in step 4.
Remember, this method works for trinomials where the coefficient of the x^2 term is 1. If the coefficient is not 1, you would need to use a different factoring method, such as the "ac method" or "factor by grouping".
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