The output of the code snippet would be "0.000000".

This is because the operation 3 / 2 is an integer division since both operands are integers. In integer division, the fractional part is discarded, and the result is an integer. So, 3 / 2 equals 1 in integer division.

However, the printf function is trying to print the result as a float ("%f"), which leads to undefined behavior. In most cases, it will print "0.000000" because the binary representation of 1 as an integer is different from its representation as a float.

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The output of the code snippet would be "0.000000".

This is because the operation 3 / 2 is an integer division since both operands are integers. In integer division, the fractional part is discarded, and the result is an integer. So, 3 / 2 equals 1 in integer division.

However, the printf function is trying to print the result as a float ("%f"), which leads to undefined behavior. In most cases, it will print "0.000000" because the binary representation of 1 as an integer is different from its representation as a float.

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The output of the code snippet would be "0.000000".

This is because the operation 3 / 2 is an integer division since both operands are integers. In integer division, the fractional part is discarded, and the result is an integer. So, 3 / 2 equals 1 in integer division.

However, the printf function is trying to print the result as a float ("%f"), which leads to undefined behavior. In most cases, it will print "0.000000" because the binary representation of 1 as an integer is different from its representation as a float.

Select the correct answerWhat is the output of the following code snippet?printf("%f", 3 / 2);Options1.0000001.5000000.0000002.000000

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